At a farm, there were
49 as many geese and goats. The farmer added another 29 geese but sold away 46 goats. In the end, there were 5 goats more than geese. How many geese and goats were there altogether in the end?
| |
Geese |
Goats |
| Before |
4 u |
9 u |
| Change |
+ 29 |
- 46 |
| After |
4 u + 29 |
9 u - 46 |
If the farmer had another 5 geese in the end, the number of geese and (chickens) would be the same.
9 u - 46 = 4 u + 29 + 5
9 u - 4 u = 34 + 46
5 u = 80
1 u = 80 ÷ 5 = 16
Number of goats and geese in the end
= 4 u + 29 + 9 u - 46
= 4 u + 9 u + 29 - 46
= 13 u - 17
= 13 x 16 - 17
= 191
Answer(s): 191
