At a farm, there were
79 as many turkeys and ducks. The farmer added another 22 turkeys but sold away 50 ducks. In the end, there were 6 ducks more than turkeys. How many turkeys and ducks were there altogether in the end?
| |
Turkeys |
Ducks |
| Before |
7 u |
9 u |
| Change |
+ 22 |
- 50 |
| After |
7 u + 22 |
9 u - 50 |
If the farmer had another 6 turkeys in the end, the number of turkeys and (chickens) would be the same.
9 u - 50 = 7 u + 22 + 6
9 u - 7 u = 28 + 50
2 u = 78
1 u = 78 ÷ 2 = 39
Number of ducks and turkeys in the end
= 7 u + 22 + 9 u - 50
= 7 u + 9 u + 22 - 50
= 16 u - 28
= 16 x 39 - 28
= 596
Answer(s): 596
