At a farm, there were
611 as many geese and goats. The farmer added another 28 geese but sold away 49 goats. In the end, there were 8 goats more than geese. How many geese and goats were there altogether in the end?
| |
Geese |
Goats |
| Before |
6 u |
11 u |
| Change |
+ 28 |
- 49 |
| After |
6 u + 28 |
11 u - 49 |
If the farmer had another 8 geese in the end, the number of geese and (chickens) would be the same.
11 u - 49 = 6 u + 28 + 8
11 u - 6 u = 36 + 49
5 u = 85
1 u = 85 ÷ 5 = 17
Number of goats and geese in the end
= 6 u + 28 + 11 u - 49
= 6 u + 11 u + 28 - 49
= 17 u - 21
= 17 x 17 - 21
= 268
Answer(s): 268
