At a farm, there were
57 as many ducks and turkeys. The farmer added another 30 ducks but sold away 43 turkeys. In the end, there were 5 turkeys more than ducks. How many ducks and turkeys were there altogether in the end?
| |
Ducks |
Turkeys |
| Before |
5 u |
7 u |
| Change |
+ 30 |
- 43 |
| After |
5 u + 30 |
7 u - 43 |
If the farmer had another 5 ducks in the end, the number of ducks and (chickens) would be the same.
7 u - 43 = 5 u + 30 + 5
7 u - 5 u = 35 + 43
2 u = 78
1 u = 78 ÷ 2 = 39
Number of turkeys and ducks in the end
= 5 u + 30 + 7 u - 43
= 5 u + 7 u + 30 - 43
= 12 u - 13
= 12 x 39 - 13
= 455
Answer(s): 455
