At a farm, there were
611 as many cows and goats. The farmer added another 34 cows but sold away 42 goats. In the end, there were 4 goats more than cows. How many cows and goats were there altogether in the end?
| |
Cows |
Goats |
| Before |
6 u |
11 u |
| Change |
+ 34 |
- 42 |
| After |
6 u + 34 |
11 u - 42 |
If the farmer had another 4 cows in the end, the number of cows and (chickens) would be the same.
11 u - 42 = 6 u + 34 + 4
11 u - 6 u = 38 + 42
5 u = 80
1 u = 80 ÷ 5 = 16
Number of goats and cows in the end
= 6 u + 34 + 11 u - 42
= 6 u + 11 u + 34 - 42
= 17 u - 8
= 17 x 16 - 8
= 264
Answer(s): 264
