At a farm, there were
411 as many sheep and geese. The farmer added another 23 sheep but sold away 49 geese. In the end, there were 5 geese more than sheep. How many sheep and geese were there altogether in the end?
| |
Sheep |
Geese |
| Before |
4 u |
11 u |
| Change |
+ 23 |
- 49 |
| After |
4 u + 23 |
11 u - 49 |
If the farmer had another 5 sheep in the end, the number of sheep and (chickens) would be the same.
11 u - 49 = 4 u + 23 + 5
11 u - 4 u = 28 + 49
7 u = 77
1 u = 77 ÷ 7 = 11
Number of geese and sheep in the end
= 4 u + 23 + 11 u - 49
= 4 u + 11 u + 23 - 49
= 15 u - 26
= 15 x 11 - 26
= 139
Answer(s): 139
