At a farm, there were
310 as many chickens and geese. The farmer added another 28 chickens but sold away 35 geese. In the end, there were 7 geese more than chickens. How many chickens and geese were there altogether in the end?
| |
Chickens |
Geese |
| Before |
3 u |
10 u |
| Change |
+ 28 |
- 35 |
| After |
3 u + 28 |
10 u - 35 |
If the farmer had another 7 chickens in the end, the number of chickens and (chickens) would be the same.
10 u - 35 = 3 u + 28 + 7
10 u - 3 u = 35 + 35
7 u = 70
1 u = 70 ÷ 7 = 10
Number of geese and chickens in the end
= 3 u + 28 + 10 u - 35
= 3 u + 10 u + 28 - 35
= 13 u - 7
= 13 x 10 - 7
= 123
Answer(s): 123
