At a farm, there were
310 as many cows and pigs. The farmer added another 35 cows but sold away 48 pigs. In the end, there were 8 pigs more than cows. How many cows and pigs were there altogether in the end?
|
Cows |
Pigs |
Before |
3 u |
10 u |
Change |
+ 35 |
- 48 |
After |
3 u + 35 |
10 u - 48 |
If the farmer had another 8 cows in the end, the number of cows and (chickens) would be the same.
10 u - 48 = 3 u + 35 + 8
10 u - 3 u = 43 + 48
7 u = 91
1 u = 91 ÷ 7 = 13
Number of pigs and cows in the end
= 3 u + 35 + 10 u - 48
= 3 u + 10 u + 35 - 48
= 13 u - 13
= 13 x 13 - 13
= 156
Answer(s): 156