At a farm, there were
59 as many sheep and goats. The farmer added another 32 sheep but sold away 42 goats. In the end, there were 6 goats more than sheep. How many sheep and goats were there altogether in the end?
| |
Sheep |
Goats |
| Before |
5 u |
9 u |
| Change |
+ 32 |
- 42 |
| After |
5 u + 32 |
9 u - 42 |
If the farmer had another 6 sheep in the end, the number of sheep and (chickens) would be the same.
9 u - 42 = 5 u + 32 + 6
9 u - 5 u = 38 + 42
4 u = 80
1 u = 80 ÷ 4 = 20
Number of goats and sheep in the end
= 5 u + 32 + 9 u - 42
= 5 u + 9 u + 32 - 42
= 14 u - 10
= 14 x 20 - 10
= 270
Answer(s): 270
