Irene and Xylia had an equal number of pens at first. Irene used
14 of her pens and Xylia used
18 of her pens. They used 6 pens altogether. How many pens did Xylia have in the end?
|
Irene |
Xylia |
Before |
4x2 = 8 u |
8x1 = 8 u |
Change |
- 1x2 = - 2 u |
- 1x1 = - 1 u |
After |
3x2 = 6 u |
7x1 = 7 u |
The number of pens that Irene and Xylia each had at first is the same. Make the number of pens that Irene and Xylia each had at first the same. LCM of 4 and 8 is 8.
Number of pens that Irene and Xylia used
= 2 u + 1 u
= 3 u
3 u = 6
1 u = 6 ÷ 3 = 2
Number of pens that Xylia had in the end
= 7 u
= 7 x 2
= 14
Answer(s): 14