Barbara and Xylia had an equal number of coins at first. Barbara used
13 of her coins and Xylia used
19 of her coins. They used 16 coins altogether. How many coins did Xylia have in the end?
| |
Barbara |
Xylia |
| Before |
3x3 =
9 u |
9x1 =
9 u |
| Change |
- 1x3 =
- 3 u |
- 1x1 =
- 1 u |
| After |
2x3 =
6 u |
8x1 =
8 u |
The number of coins that Barbara and Xylia each had at first is the same. Make the number of coins that Barbara and Xylia each had at first the same. LCM of 3 and 9 is 9.
Number of coins that Barbara and Xylia used
= 3 u + 1 u
= 4 u
4 u = 16
1 u = 16 ÷ 4 = 4
Number of coins that Xylia had in the end
= 8 u
= 8 x 4
= 32
Answer(s): 32
