Jade and Hilda had an equal number of coins at first. Jade used
14 of her coins and Hilda used
18 of her coins. They used 12 coins altogether. How many coins did Hilda have in the end?
| |
Jade |
Hilda |
| Before |
4x2 =
8 u |
8x1 =
8 u |
| Change |
- 1x2 =
- 2 u |
- 1x1 =
- 1 u |
| After |
3x2 =
6 u |
7x1 =
7 u |
The number of coins that Jade and Hilda each had at first is the same. Make the number of coins that Jade and Hilda each had at first the same. LCM of 4 and 8 is 8.
Number of coins that Jade and Hilda used
= 2 u + 1 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Hilda had in the end
= 7 u
= 7 x 4
= 28
Answer(s): 28
