There were 291 persimmons and apples in a fruit stall.
37 of the persimmons and
35 of apples were sold. Given that there were 198 persimmons and apples left, how many persimmons were there in the fruit stall at first?
|
Persimmons |
Apples |
Before |
7 u |
5 p |
Change |
- 3 u |
- 3 p |
After |
4 u |
2 p |
7 u + 5 p = 291 --- (1)
4 u + 2 p = 198 --- (2)
Make p the same.
(1)
x 2 14 u + 10 p = 582 --- (3)
(2)
x 5 20 u + 10 p = 990 --- (4)
(4) - (3)
20 u - 14 u = 990 - 582
6 u = 408
1 u = 408 ÷ 6 = 68
Number of persimmons at first
= 7 u
= 7 x 68
= 476
Answer(s): 476