There were 268 pomegranates and kiwis in a fruit stall.
310 of the pomegranates and
38 of kiwis were sold. Given that there were 199 pomegranates and kiwis left, how many pomegranates were there in the fruit stall at first?
| |
Pomegranates |
Kiwis |
| Before |
10 u |
8 p |
| Change |
- 3 u |
- 3 p |
| After |
7 u |
5 p |
10 u + 8 p = 268 --- (1)
7 u + 5 p = 199 --- (2)
Make p the same.
(1)
x 5 50 u + 40 p = 1340 --- (3)
(2)
x 8 56 u + 40 p = 1592 --- (4)
(4) - (3)
56 u - 50 u = 1592 - 1340
6 u = 252
1 u = 252 ÷ 6 = 42
Number of pomegranates at first
= 10 u
= 10 x 42
= 420
Answer(s): 420
