Pierre and Hazel had equal amount of money. Pierre spent
12 of his money on a jumpsuit while Hazel spent
23 of her money on a sweater. Given that Hazel spent $11 more than Pierre, how much did Pierre have at first?
| |
Pierre |
Hazel |
| Before |
2x3 =
6 u |
3x2 =
6 u |
| Change |
- 1x3 =
- 3 u |
- 2x2 =
- 4 u |
| After |
1x3 =
3 u |
1x2 =
2 u |
The amount that Pierre and Hazel had at first is the same. Make the amount that Pierre and Hazel had at first the same. LCM of 2 and 3 is 6.
Amount that Hazel spent more than Pierre
= 4 u - 3 u
= 1 u
1 u = 11
Amount that Pierre had at first
= 6 u
= 6 x 11
= $66
Answer(s): $66
