Vincent and Ivan had the same number of pens. Vincent gave away
57 of his pens while Ivan gave away
35 of his pens. Given that Vincent gave away 12 pens more than Ivan, how many pens did Vincent have at first?
| |
Vincent's pens |
Ivan's pens |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Vincent and Ivan each had at first is the same. Make the number of cards that Vincent and Ivan each had at first the same. LCM of 7 and 5 is 35.
Number of pens that Vincent gave away more than Ivan
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of pens that Vincent had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
