Zane and Seth had the same number of pens. Zane gave away
34 of his pens while Seth gave away
35 of his pens. Given that Zane gave away 12 pens more than Seth, how many pens did Zane have at first?
| |
Zane's pens |
Seth's pens |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Zane and Seth each had at first is the same. Make the number of cards that Zane and Seth each had at first the same. LCM of 4 and 5 is 20.
Number of pens that Zane gave away more than Seth
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of pens that Zane had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
