Nick and Caden had the same number of coins. Nick gave away
34 of his coins while Caden gave away
35 of his coins. Given that Nick gave away 12 coins more than Caden, how many coins did Nick have at first?
|
Nick's coins |
Caden's coins |
Before |
4x5 = 20 u |
5x4 = 20 u |
Change |
- 3x5 = - 15 u |
- 3x4 = - 12 u |
After |
1x5 = 5 u |
2x4 = 8 u |
The number of cards that Nick and Caden each had at first is the same. Make the number of cards that Nick and Caden each had at first the same. LCM of 4 and 5 is 20.
Number of coins that Nick gave away more than Caden
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Nick had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80