Elijah and Eric had the same number of coins. Elijah gave away
45 of his coins while Eric gave away
23 of his coins. Given that Elijah gave away 12 coins more than Eric, how many coins did Elijah have at first?
| |
Elijah's coins |
Eric's coins |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Elijah and Eric each had at first is the same. Make the number of cards that Elijah and Eric each had at first the same. LCM of 5 and 3 is 15.
Number of coins that Elijah gave away more than Eric
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of coins that Elijah had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
