Lee and Vincent had the same number of marbles. Lee gave away
45 of his marbles while Vincent gave away
23 of his marbles. Given that Lee gave away 12 marbles more than Vincent, how many marbles did Lee have at first?
| |
Lee's marbles |
Vincent's marbles |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Lee and Vincent each had at first is the same. Make the number of cards that Lee and Vincent each had at first the same. LCM of 5 and 3 is 15.
Number of marbles that Lee gave away more than Vincent
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of marbles that Lee had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
