Nick and Will had the same number of beads. Nick gave away
45 of his beads while Will gave away
23 of his beads. Given that Nick gave away 12 beads more than Will, how many beads did Nick have at first?
| |
Nick's beads |
Will's beads |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Nick and Will each had at first is the same. Make the number of cards that Nick and Will each had at first the same. LCM of 5 and 3 is 15.
Number of beads that Nick gave away more than Will
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of beads that Nick had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
