Japheth and Howard had the same number of coins. Japheth gave away
57 of his coins while Howard gave away
35 of his coins. Given that Japheth gave away 12 coins more than Howard, how many coins did Japheth have at first?
| |
Japheth's coins |
Howard's coins |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Japheth and Howard each had at first is the same. Make the number of cards that Japheth and Howard each had at first the same. LCM of 7 and 5 is 35.
Number of coins that Japheth gave away more than Howard
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of coins that Japheth had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
