Peter and Luke had the same number of coins. Peter gave away
34 of his coins while Luke gave away
35 of his coins. Given that Peter gave away 12 coins more than Luke, how many coins did Peter have at first?
| |
Peter's coins |
Luke's coins |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Peter and Luke each had at first is the same. Make the number of cards that Peter and Luke each had at first the same. LCM of 4 and 5 is 20.
Number of coins that Peter gave away more than Luke
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Peter had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
