Daniel and Justin had the same number of pens. Daniel gave away
57 of his pens while Justin gave away
35 of his pens. Given that Daniel gave away 12 pens more than Justin, how many pens did Daniel have at first?
| |
Daniel's pens |
Justin's pens |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Daniel and Justin each had at first is the same. Make the number of cards that Daniel and Justin each had at first the same. LCM of 7 and 5 is 35.
Number of pens that Daniel gave away more than Justin
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of pens that Daniel had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
