Vaidev and Fred had the same number of coins. Vaidev gave away
34 of his coins while Fred gave away
35 of his coins. Given that Vaidev gave away 12 coins more than Fred, how many coins did Vaidev have at first?
| |
Vaidev's coins |
Fred's coins |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Vaidev and Fred each had at first is the same. Make the number of cards that Vaidev and Fred each had at first the same. LCM of 4 and 5 is 20.
Number of coins that Vaidev gave away more than Fred
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Vaidev had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
