Perry and Peter had the same number of beads. Perry gave away
57 of his beads while Peter gave away
35 of his beads. Given that Perry gave away 12 beads more than Peter, how many beads did Perry have at first?
| |
Perry's beads |
Peter's beads |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Perry and Peter each had at first is the same. Make the number of cards that Perry and Peter each had at first the same. LCM of 7 and 5 is 35.
Number of beads that Perry gave away more than Peter
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of beads that Perry had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
