Bobby and Pierre had the same number of pens. Bobby gave away
34 of his pens while Pierre gave away
35 of his pens. Given that Bobby gave away 12 pens more than Pierre, how many pens did Bobby have at first?
| |
Bobby's pens |
Pierre's pens |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Bobby and Pierre each had at first is the same. Make the number of cards that Bobby and Pierre each had at first the same. LCM of 4 and 5 is 20.
Number of pens that Bobby gave away more than Pierre
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of pens that Bobby had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
