Daniel and Vincent had the same number of coins. Daniel gave away
45 of his coins while Vincent gave away
23 of his coins. Given that Daniel gave away 12 coins more than Vincent, how many coins did Daniel have at first?
| |
Daniel's coins |
Vincent's coins |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Daniel and Vincent each had at first is the same. Make the number of cards that Daniel and Vincent each had at first the same. LCM of 5 and 3 is 15.
Number of coins that Daniel gave away more than Vincent
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of coins that Daniel had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
