Cody and Riordan had the same number of coins. Cody gave away
57 of his coins while Riordan gave away
35 of his coins. Given that Cody gave away 12 coins more than Riordan, how many coins did Cody have at first?
| |
Cody's coins |
Riordan's coins |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Cody and Riordan each had at first is the same. Make the number of cards that Cody and Riordan each had at first the same. LCM of 7 and 5 is 35.
Number of coins that Cody gave away more than Riordan
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of coins that Cody had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
