Dylan and Gabriel had the same number of beads. Dylan gave away
45 of his beads while Gabriel gave away
23 of his beads. Given that Dylan gave away 12 beads more than Gabriel, how many beads did Dylan have at first?
| |
Dylan's beads |
Gabriel's beads |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Dylan and Gabriel each had at first is the same. Make the number of cards that Dylan and Gabriel each had at first the same. LCM of 5 and 3 is 15.
Number of beads that Dylan gave away more than Gabriel
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of beads that Dylan had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
