John and Eric had the same number of cards. John gave away
45 of his cards while Eric gave away
23 of his cards. Given that John gave away 12 cards more than Eric, how many cards did John have at first?
| |
John's cards |
Eric's cards |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that John and Eric each had at first is the same. Make the number of cards that John and Eric each had at first the same. LCM of 5 and 3 is 15.
Number of cards that John gave away more than Eric
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of cards that John had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
