Liam and Jeremy had the same number of cards. Liam gave away
57 of his cards while Jeremy gave away
35 of his cards. Given that Liam gave away 12 cards more than Jeremy, how many cards did Liam have at first?
| |
Liam's cards |
Jeremy's cards |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Liam and Jeremy each had at first is the same. Make the number of cards that Liam and Jeremy each had at first the same. LCM of 7 and 5 is 35.
Number of cards that Liam gave away more than Jeremy
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of cards that Liam had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
