George and Xavier had the same number of cards. George gave away
45 of his cards while Xavier gave away
23 of his cards. Given that George gave away 12 cards more than Xavier, how many cards did George have at first?
| |
George's cards |
Xavier's cards |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that George and Xavier each had at first is the same. Make the number of cards that George and Xavier each had at first the same. LCM of 5 and 3 is 15.
Number of cards that George gave away more than Xavier
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of cards that George had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
