Pierre and Cole had the same number of stickers. Pierre gave away
34 of his stickers while Cole gave away
35 of his stickers. Given that Pierre gave away 12 stickers more than Cole, how many stickers did Pierre have at first?
| |
Pierre's stickers |
Cole's stickers |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Pierre and Cole each had at first is the same. Make the number of cards that Pierre and Cole each had at first the same. LCM of 4 and 5 is 20.
Number of stickers that Pierre gave away more than Cole
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of stickers that Pierre had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
