Brandon and Glen had the same number of coins. Brandon gave away
34 of his coins while Glen gave away
35 of his coins. Given that Brandon gave away 12 coins more than Glen, how many coins did Brandon have at first?
| |
Brandon's coins |
Glen's coins |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Brandon and Glen each had at first is the same. Make the number of cards that Brandon and Glen each had at first the same. LCM of 4 and 5 is 20.
Number of coins that Brandon gave away more than Glen
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Brandon had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
