Sean and Ivan had the same number of stamps. Sean gave away
57 of his stamps while Ivan gave away
35 of his stamps. Given that Sean gave away 12 stamps more than Ivan, how many stamps did Sean have at first?
| |
Sean's stamps |
Ivan's stamps |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Sean and Ivan each had at first is the same. Make the number of cards that Sean and Ivan each had at first the same. LCM of 7 and 5 is 35.
Number of stamps that Sean gave away more than Ivan
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of stamps that Sean had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
