Billy and Cody had the same number of coins. Billy gave away
34 of his coins while Cody gave away
35 of his coins. Given that Billy gave away 12 coins more than Cody, how many coins did Billy have at first?
| |
Billy's coins |
Cody's coins |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Billy and Cody each had at first is the same. Make the number of cards that Billy and Cody each had at first the same. LCM of 4 and 5 is 20.
Number of coins that Billy gave away more than Cody
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Billy had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
