John and Fred had the same number of coins. John gave away
45 of his coins while Fred gave away
23 of his coins. Given that John gave away 12 coins more than Fred, how many coins did John have at first?
| |
John's coins |
Fred's coins |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that John and Fred each had at first is the same. Make the number of cards that John and Fred each had at first the same. LCM of 5 and 3 is 15.
Number of coins that John gave away more than Fred
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of coins that John had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
