Seth and Neave had the same number of beads. Seth gave away
34 of his beads while Neave gave away
35 of his beads. Given that Seth gave away 12 beads more than Neave, how many beads did Seth have at first?
| |
Seth's beads |
Neave's beads |
| Before |
4x5 =
20 u |
5x4 =
20 u |
| Change |
- 3x5 =
- 15 u |
- 3x4 =
- 12 u |
| After |
1x5 =
5 u |
2x4 =
8 u |
The number of cards that Seth and Neave each had at first is the same. Make the number of cards that Seth and Neave each had at first the same. LCM of 4 and 5 is 20.
Number of beads that Seth gave away more than Neave
= 15 u - 12 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of beads that Seth had at first
= 20 u
= 20 x 4
= 80
Answer(s): 80
