Howard and Brandon had the same number of buttons. Howard gave away
45 of his buttons while Brandon gave away
23 of his buttons. Given that Howard gave away 12 buttons more than Brandon, how many buttons did Howard have at first?
| |
Howard's buttons |
Brandon's buttons |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Howard and Brandon each had at first is the same. Make the number of cards that Howard and Brandon each had at first the same. LCM of 5 and 3 is 15.
Number of buttons that Howard gave away more than Brandon
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of buttons that Howard had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
