Julian and Luis had the same number of cards. Julian gave away
45 of his cards while Luis gave away
23 of his cards. Given that Julian gave away 12 cards more than Luis, how many cards did Julian have at first?
| |
Julian's cards |
Luis's cards |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Julian and Luis each had at first is the same. Make the number of cards that Julian and Luis each had at first the same. LCM of 5 and 3 is 15.
Number of cards that Julian gave away more than Luis
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of cards that Julian had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
