Seth and Daniel had the same number of beads. Seth gave away
45 of his beads while Daniel gave away
23 of his beads. Given that Seth gave away 12 beads more than Daniel, how many beads did Seth have at first?
| |
Seth's beads |
Daniel's beads |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Seth and Daniel each had at first is the same. Make the number of cards that Seth and Daniel each had at first the same. LCM of 5 and 3 is 15.
Number of beads that Seth gave away more than Daniel
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of beads that Seth had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
