Tom and Vaidev had the same number of cards. Tom gave away
57 of his cards while Vaidev gave away
35 of his cards. Given that Tom gave away 12 cards more than Vaidev, how many cards did Tom have at first?
| |
Tom's cards |
Vaidev's cards |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Tom and Vaidev each had at first is the same. Make the number of cards that Tom and Vaidev each had at first the same. LCM of 7 and 5 is 35.
Number of cards that Tom gave away more than Vaidev
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of cards that Tom had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
