Perry and Ken had the same number of cards. Perry gave away
45 of his cards while Ken gave away
23 of his cards. Given that Perry gave away 12 cards more than Ken, how many cards did Perry have at first?
| |
Perry's cards |
Ken's cards |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Perry and Ken each had at first is the same. Make the number of cards that Perry and Ken each had at first the same. LCM of 5 and 3 is 15.
Number of cards that Perry gave away more than Ken
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of cards that Perry had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
