Perry and Jenson had the same number of pens. Perry gave away
45 of his pens while Jenson gave away
23 of his pens. Given that Perry gave away 12 pens more than Jenson, how many pens did Perry have at first?
| |
Perry's pens |
Jenson's pens |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Perry and Jenson each had at first is the same. Make the number of cards that Perry and Jenson each had at first the same. LCM of 5 and 3 is 15.
Number of pens that Perry gave away more than Jenson
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of pens that Perry had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
