Liam and Harry had the same number of coins. Liam gave away
57 of his coins while Harry gave away
35 of his coins. Given that Liam gave away 12 coins more than Harry, how many coins did Liam have at first?
| |
Liam's coins |
Harry's coins |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Liam and Harry each had at first is the same. Make the number of cards that Liam and Harry each had at first the same. LCM of 7 and 5 is 35.
Number of coins that Liam gave away more than Harry
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of coins that Liam had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
