Lee and Wesley had the same number of beads. Lee gave away
45 of his beads while Wesley gave away
23 of his beads. Given that Lee gave away 12 beads more than Wesley, how many beads did Lee have at first?
| |
Lee's beads |
Wesley's beads |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Lee and Wesley each had at first is the same. Make the number of cards that Lee and Wesley each had at first the same. LCM of 5 and 3 is 15.
Number of beads that Lee gave away more than Wesley
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of beads that Lee had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
