Brandon and Carl had the same number of coins. Brandon gave away
45 of his coins while Carl gave away
23 of his coins. Given that Brandon gave away 12 coins more than Carl, how many coins did Brandon have at first?
| |
Brandon's coins |
Carl's coins |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Brandon and Carl each had at first is the same. Make the number of cards that Brandon and Carl each had at first the same. LCM of 5 and 3 is 15.
Number of coins that Brandon gave away more than Carl
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of coins that Brandon had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
