Daniel and Mark had the same number of buttons. Daniel gave away
45 of his buttons while Mark gave away
23 of his buttons. Given that Daniel gave away 12 buttons more than Mark, how many buttons did Daniel have at first?
| |
Daniel's buttons |
Mark's buttons |
| Before |
5x3 =
15 u |
3x5 =
15 u |
| Change |
- 4x3 =
- 12 u |
- 2x5 =
- 10 u |
| After |
1x3 =
3 u |
1x5 =
5 u |
The number of cards that Daniel and Mark each had at first is the same. Make the number of cards that Daniel and Mark each had at first the same. LCM of 5 and 3 is 15.
Number of buttons that Daniel gave away more than Mark
= 12 u - 10 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of buttons that Daniel had at first
= 15 u
= 15 x 6
= 90
Answer(s): 90
