Daniel and Brandon had the same number of erasers. Daniel gave away
57 of his erasers while Brandon gave away
35 of his erasers. Given that Daniel gave away 12 erasers more than Brandon, how many erasers did Daniel have at first?
| |
Daniel's erasers |
Brandon's erasers |
| Before |
7x5 =
35 u |
5x7 =
35 u |
| Change |
- 5x5 =
- 25 u |
- 3x7 =
- 21 u |
| After |
2x5 =
10 u |
2x7 =
14 u |
The number of cards that Daniel and Brandon each had at first is the same. Make the number of cards that Daniel and Brandon each had at first the same. LCM of 7 and 5 is 35.
Number of erasers that Daniel gave away more than Brandon
= 25 u - 21 u
= 4 u
4 u = 12
1 u = 12 ÷ 4 = 3
Number of erasers that Daniel had at first
= 35 u
= 35 x 3
= 105
Answer(s): 105
